Complete Summary and Solutions for Electrostatic Potential and Capacitance – NCERT Class XII Physics Part I, Chapter 2 – Potential Due to Point Charge, Equipotential Surfaces, Capacitors

Detailed summary and explanation of Chapter 2 'Electrostatic Potential and Capacitance' from the NCERT Class XII Physics Part I textbook, covering concepts of electrostatic potential, potential difference, equipotential surfaces, calculation of potential due to point charge and system of charges, capacitors, capacitance, combination of capacitors, energy stored in capacitors, and applications—along with all NCERT questions and solutions.

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Categories: NCERT, Class XII, Physics Part I, Chapter 2, Electrostatic Potential, Capacitance, Capacitors, Equipotential Surfaces, Summary, Questions, Answers
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Electrostatic Potential and Capacitance - Class 12 Physics Chapter 2 Ultimate Study Guide 2025

Electrostatic Potential and Capacitance

Chapter 2: Physics - Ultimate Study Guide | NCERT Class 12 Notes, Questions, Derivations & Quiz 2025

Full Chapter Summary & Detailed Notes - Electrostatic Potential and Capacitance Class 12 NCERT

Overview & Key Concepts

  • Chapter Goal: Understand electrostatic potential, energy, capacitance. Exam Focus: Conservative forces, potential due to charges, capacitors; 2025 Updates: Applications (e.g., batteries, energy storage). Fun Fact: Volta's pile origin. Core Idea: Potential as work per charge. Real-World: Capacitors in devices. Expanded: All subtopics point-wise with evidence (e.g., Fig 2.1 test charge), examples (e.g., spring analogy), debates (path independence).
  • Wider Scope: From conservative forces to dielectrics; sources: Text, figures (2.1-2.8), examples.
  • Expanded Content: Include calculations, graphs; links (e.g., to mechanics energy); point-wise breakdown.

2.1 Introduction

  • Summary: In Chapters 5 and 7 (Class XI), the notion of potential energy was introduced. When an external force does work in taking a body from a point to another against a force like spring force or gravitational force, that work gets stored as potential energy of the body. When the external force is removed, the body moves, gaining kinetic energy and losing an equal amount of potential energy. The sum of kinetic and potential energies is thus conserved. Forces of this kind are called conservative forces. Spring force and gravitational force are examples of conservative forces.
  • Coulomb force between two (stationary) charges is also a conservative force. This is not surprising, since both have inverse-square dependence on distance and differ mainly in the proportionality constants – the masses in the gravitational law are replaced by charges in Coulomb’s law. Thus, like the potential energy of a mass in a gravitational field, we can define electrostatic potential energy of a charge in an electrostatic field.
  • Consider an electrostatic field E due to some charge configuration. First, for simplicity, consider the field E due to a charge Q placed at the origin. Now, imagine that we bring a test charge q from a point R to a point P against the repulsive force on it due to the charge Q. With reference to Fig. 2.1, this will happen if Q and q are both positive or both negative. For definiteness, let us take Q, q > 0.
  • Conservative Forces: Work stored as potential energy; examples: spring, gravity.
  • Coulomb Force: Conservative; inverse-square like gravity.
  • Electrostatic Potential Energy: Work against field stored.
  • Expanded: Evidence: Analogy to mechanics; debates: Conservative vs non; real: Energy conservation in fields.
Conceptual Diagram: Test Charge Movement

Test charge q from R to P against Q; arrows show forces.

2.2 Electrostatic Potential

  • Summary: Two remarks may be made here. First, we assume that the test charge q is so small that it does not disturb the original configuration, namely the charge Q at the origin (or else, we keep Q fixed at the origin by some unspecified force). Second, in bringing the charge q from R to P, we apply an external force Fext just enough to counter the repulsive electric force FE (i.e, Fext= –FE). This means there is no net force on or acceleration of the charge q when it is brought from R to P, i.e., it is brought with infinitesimally slow constant speed. In this situation, work done by the external force is the negative of the work done by the electric force, and gets fully stored in the form of potential energy of the charge q. If the external force is removed on reaching P, the electric force will take the charge away from Q – the stored energy (potential energy) at P is used to provide kinetic energy to the charge q in such a way that the sum of the kinetic and potential energies is conserved.
  • Thus, work done by external forces in moving a charge q from R to P is WRP = ∫ Fext · dr = - ∫ FE · dr.
  • This work done is against electrostatic repulsive force and gets stored as potential energy.
  • At every point in electric field, a particle with charge q possesses a certain electrostatic potential energy, this work done increases its potential energy by an amount equal to potential energy difference between points R and P.
  • Thus, potential energy difference ΔU = UP - UR = WRP.
  • (Note here that this displacement is in an opposite sense to the electric force and hence work done by electric field is negative, i.e., –WRP.)
  • Therefore, we can define electric potential energy difference between two points as the work required to be done by an external force in moving (without accelerating) charge q from one point to another for electric field of any arbitrary charge configuration.
  • Two Important Comments: (i) The right side of Eq. (2.2) depends only on the initial and final positions of the charge. It means that the work done by an electrostatic field in moving a charge from one point to another depends only on the initial and the final points and is independent of the path taken to go from one point to the other. This is the fundamental characteristic of a conservative force. The concept of the potential energy would not be meaningful if the work depended on the path. The path-independence of work done by an electrostatic field can be proved using the Coulomb’s law. We omit this proof here.
  • (ii) Equation (2.2) defines potential energy difference in terms of the physically meaningful quantity work. Clearly, potential energy so defined is undetermined to within an additive constant.What this means is that the actual value of potential energy is not physically significant; it is only the difference of potential energy that is significant. We can always add an arbitrary constant α to potential energy at every point, since this will not change the potential energy difference: (UP + α) - (UR + α) = UP - UR.
  • Put it differently, there is a freedom in choosing the point where potential energy is zero. A convenient choice is to have electrostatic potential energy zero at infinity. With this choice, if we take the point R at infinity, we get from Eq. (2.2) WP = UP - U∞ = UP (since U∞ = 0).
  • Since the point P is arbitrary, this provides us with a definition of potential energy of a charge q at any point. Potential energy of charge q at a point (in the presence of field due to any charge configuration) is the work done by the external force (equal and opposite to the electric force) in bringing the charge q from infinity to that point.
  • Work Done: By external force = - work by electric force.
  • Path Independence: Work depends only on endpoints.
  • Zero at Infinity: Convenient choice for U∞ = 0.
  • Expanded: Evidence: Fig 2.2 path independence; debates: Additive constant; real: Energy storage in fields.

2.3 Potential Due to a Point Charge

  • Summary: Consider any general static charge configuration. We define potential energy of a test charge q in terms of the work done on the charge q. This work is obviously proportional to q, since the force at any point is qE, where E is the electric field at that point due to the given charge configuration. It is, therefore, convenient to divide the work by the amount of charge q, so that the resulting quantity is independent of q. In other words, work done per unit test charge is characteristic of the electric field associated with the charge configuration. This leads to the idea of electrostatic potential V due to a given charge configuration. From Eq. (2.1), we get: Work done by external force in bringing a unit positive charge from point R to P = VP – VR = (UP - UR)/q.
  • Where VP and VR are the electrostatic potentials at P and R, respectively. Note, as before, that it is not the actual value of potential but the potential difference that is physically significant. If, as before, we choose the potential to be zero at infinity, Eq. (2.4) implies: Work done by an external force in bringing a unit positive charge from infinity to a point = electrostatic potential (V) at that point.
  • In other words, the electrostatic potential (V) at any point in a region with electrostatic field is the work done in bringing a unit positive charge (without acceleration) from infinity to that point.
  • The qualifying remarks made earlier regarding potential energy also apply to the definition of potential. To obtain the work done per unit test charge, we should take an infinitesimal test charge δq, obtain the work done δW in bringing it from infinity to the point and determine the ratio δW/δq. Also, the external force at every point of the path is to be equal and opposite to the electrostatic force on the test charge at that point.
  • Potential Definition: V = work per unit charge from infinity.
  • Count Alessandro Volta: Developed voltaic pile (battery).
  • Expanded: Evidence: Fig 2.3 work for point charge; real: Battery potential.
Conceptual Diagram: Potential Variation

V vs r (blue), E vs r (black) for point charge.

2.4 Potential Due to an Electric Dipole

  • Summary: Consider a point charge Q at the origin (Fig. 2.3). For definiteness, take Q to be positive. We wish to determine the potential at any point P with position vector r from the origin. For that we must calculate the work done in bringing a unit positive test charge from infinity to the point P. For Q > 0, the work done against the repulsive force on the test charge is positive. Since work done is independent of the path, we choose a convenient path – along the radial direction from infinity to the point P.
  • At some intermediate point P′ on the path, the electrostatic force on a unit positive charge is (Q / (4πε0 r'^2)) r̂', where r̂' is the unit vector along OP′. Work done against this force from r′ to r′ + Δr′ is ΔW = - (Q / (4πε0 r'^2)) Δr′.
  • The negative sign appears because for Δr′ < 0, ΔW is positive. Total work done (W) by the external force is obtained by integrating from r′ = ∞ to r′ = r, W = Q / (4πε0 r).
  • This, by definition is the potential at P due to the charge Q V(r) = Q / (4πε0 r).
  • Equation (2.8) is true for any sign of the charge Q, though we considered Q > 0 in its derivation. For Q < 0, V < 0, i.e., work done (by the external force) per unit positive test charge in bringing it from infinity to the point is negative. This is equivalent to saying that work done by the electrostatic force in bringing the unit positive charge from infinity to the point P is positive. [This is as it should be, since for Q < 0, the force on a unit positive test charge is attractive, so that the electrostatic force and the displacement (from infinity to P) are in the same direction.] Finally, we note that Eq. (2.8) is consistent with the choice that potential at infinity be zero.
  • Figure (2.4) shows how the electrostatic potential (∝1/r) and the electrostatic field (∝1/r^2) varies with r.
  • Derivation Steps: Integrate work along radial path.
  • Sign Consideration: Positive for repulsion, negative for attraction.
  • Expanded: Evidence: Eq. (2.5-2.8); debates: Infinity zero; real: Potential in circuits.

2.5 Potential Due to a System of Charges

  • Summary: As we learnt in the last chapter, an electric dipole consists of two charges q and –q separated by a (small) distance 2a. Its total charge is zero. It is characterised by a dipole moment vector p whose magnitude is q × 2a and which points in the direction from –q to q (Fig. 2.5). We also saw that the electric field of a dipole at a point with position vector r depends not just on the magnitude r, but also on the angle between r and p. Further, the field falls off, at large distance, not as 1/r^2 (typical of field due to a single charge) but as 1/r^3. We, now, determine the electric potential due to a dipole and contrast it with the potential due to a single charge.
  • As before, we take the origin at the centre of the dipole. Now we know that the electric field obeys the superposition principle. Since potential is related to the work done by the field, electrostatic potential also follows the superposition principle. Thus, the potential due to the dipole is the sum of potentials due to the charges q and –q V = (1/(4πε0)) [q/r1 - q/r2].
  • Where r1 and r2 are the distances of the point P from q and –q, respectively.
  • Now, by geometry, r1^2 = r^2 + a^2 - 2ar cosθ, r2^2 = r^2 + a^2 + 2ar cosθ.
  • We take r much greater than a (a << r) and retain terms only upto the first order in a/r, r1 ≈ r (1 - (a/r) cosθ), r2 ≈ r (1 + (a/r) cosθ).
  • Using the Binomial theorem and retaining terms upto the first order in a/r; we obtain, 1/r1 ≈ (1/r) (1 + (a/r) cosθ), 1/r2 ≈ (1/r) (1 - (a/r) cosθ).
  • Using Eqs. (2.9) and (2.13) and p = 2qa, we get V = (1/(4πε0)) (p cosθ / r^2).
  • Now, p cos θ = p · r̂. The electric potential of a dipole is then given by V = (1/(4πε0)) (p · r̂ / r^2); (r >> a).
  • Equation (2.15) is, as indicated, approximately true only for distances large compared to the size of the dipole, so that higher order terms in a/r are negligible. For a point dipole p at the origin, Eq. (2.15) is, however, exact.
  • From Eq. (2.15), potential on the dipole axis (θ = 0, π) is given by V = ± (1/(4πε0)) (p / r^2).
  • (Positive sign for θ = 0, negative sign for θ = π.) The potential in the equatorial plane (θ = π/2) is zero.
  • The important contrasting features of electric potential of a dipole from that due to a single charge are clear from Eqs. (2.8) and (2.15): (i) The potential due to a dipole depends not just on r but also on the angle between the position vector r and the dipole moment vector p. (It is, however, axially symmetric about p. That is, if you rotate the position vector r about p, keeping θ fixed, the points corresponding to P on the cone so generated will have the same potential as at P.) (ii) The electric dipole potential falls off, at large distance, as 1/r^2, not as 1/r, characteristic of the potential due to a single charge. (You can refer to the Fig. 2.5 for graphs of 1/r^2 versus r and 1/r versus r, drawn there in another context.)
  • Dipole Potential: V = (1/(4πε0)) (p cosθ / r^2).
  • Axial/Equatorial: Non-zero axial, zero equatorial.
  • Expanded: Evidence: Fig 2.5 quantities; debates: Approximation r>>a; real: Molecular dipoles.

Key Themes & Tips

  • Aspects: Potential, energy, capacitance.
  • Tip: Memorize formulas; path independence; differentiate potential/energy.

Project & Group Ideas

  • Build simple capacitor.
  • Debate: Dielectrics effects.
  • Simulate potential fields.